How the 2026 F1 championship is clinched: points, sprints and tiebreakers explained

A grand prix is worth at most 25 points to a driver and at most 43 to a team. A sprint is worth at most 8 and at most 15. Nine grands prix and one sprint are left in the 2026 season, and multiplying those two lines out gives 233 and 402. Every clinch number and every elimination call on this site is one subtraction away from one of those two figures.

The figures here are as of the September 20 update. The season is complete through the Spanish Grand Prix on Sunday, September 13, round 14 of 23, and nothing has run since. The next race is Azerbaijan on September 26.

The points table does the work. A grand prix pays the top ten, 25 down to 1, and the win is 25. A sprint pays the top eight, 8 down to 1, and the sprint win is 8. A team enters two cars, so a team's best possible grand prix is a one two finish, 25 plus 18, which is 43, and its best possible sprint is 8 plus 7, which is 15. Nine grands prix at 25 is 225, plus the 8 from the one sprint that remains, is 233. Nine grands prix at 43 is 387, plus 15, is 402. Nothing is added for a fastest lap.

The constructors' table is written in bigger units, which is not the same as being further along. Mercedes leads Ferrari by 145 points. Antonelli leads Russell by 81. The first gap looks close to twice the second. Divide each by what is still available and the difference almost disappears. 145 is 36 percent of the 402 a team can still win. 81 is 35 percent of the 233 a driver can still win. A team's ceiling is just over 1.7 times a driver's, and both leads have simply scaled with it. The same holds at the top of each table: Antonelli needs 66 percent of what is left to him, Mercedes 64 percent of what is left to it.

A clinch number is one subtraction. Take the nearest rival's ceiling, which is their current total plus everything still available, add one point, then subtract the leader's own total. Russell has 211 and can finish on 444. Antonelli has 292. 445 minus 292 is 153. Ferrari has 358 and can finish on 760. Mercedes has 503. 761 minus 503 is 258. That 258 is exactly six one two finishes out of the nine grands prix left, because six times 43 is 258. The 153 does not land on a round number of wins: six grand prix victories is 150, three short, and the Singapore sprint win would carry it to 158. Only the leader gets a clinch number. The car in second has none, because no run of its own results settles anything while the car in front can keep scoring.

Elimination is one comparison. A driver is out when the gap to the leader is larger than what is still available. Written the other way it is a cut line: the leader's current total minus the maximum still to be won. For drivers that is 292 minus 233, which is 59 points. Lawson sits on exactly 59, which is why his gap is exactly 233, why his ceiling is exactly 292, and why the next paragraph has to deal with him. For teams the line is 503 minus 402, which is 101, and the RB F1 Team on 77 is the first name below it, 24 short. Everyone under either line is finished. The full alive or out column is on.

Two modelling choices are worth stating, because both of them cost the leader. First, the clinch adds that one point, so a leader has to finish clear of the rival's ceiling rather than level with it. Second, elimination uses the opposite test: a chaser whose ceiling exactly matches the leader's current total stays on the board. F1 itself does not leave a points tie unresolved. It breaks one on a countback of wins, and we do not model that countback. The tiebreak is usually quoted as 8 wins to 0 in Antonelli's favour, and on today's table it is. In the only tie that can actually happen it is 9 to 8 the other way. Lawson reaches his ceiling of 292 only by winning all nine remaining grands prix and the sprint, which would leave him on nine grand prix wins. Antonelli can be tied on 292 only by scoring nothing more, which leaves him on eight. A table that applied today's win counts to a future tie would get this one backwards, which is exactly why we do not apply it.

Round 15 is Azerbaijan at the Baku City Circuit on September 26, and its first effect is mechanical. It takes 25 off every driver's remaining ceiling and 43 off every team's, leaving 208 and 359. The cut lines move with it. Even if Antonelli scores nothing in Baku, the driver line rises from 59 to 84, and Lawson can only stay level with it by winning the race. The team line rises from 101 to at least 144. The only other date that changes the shape of the sum is October 11, the last sprint of the season and the final 8 points a driver and 15 a team can take outside a grand prix. After that weekend the arithmetic is the simplest it has been all year: six grands prix flat, 150 points for a driver and 258 for a team, with the sprint's odd 8 and 15 out of the sum for good. The rest of the calendar is at.

How to read these numbers. A magic or clinch number is the minimum a leader still has to score to be certain of the title even if every rival takes everything left on the table. A tragic number is its mirror, the point after which the outcome is impossible even if you take everything left yourself. A points championship has no losses to count, so that side is expressed as a ceiling instead, the current total plus the maximum still available, measured against the leader. Ties are counted against the driver or team whose clinch is being tested, so a confirmation here can trail an official announcement by a round, and F1 rounds are a week or more apart. The live tables are at, the remaining schedule at, the working behind every figure at, and the same arithmetic run for a single entrant at and.